Question

A survey team is trying to estimate the height of a mountain above a level plain. From one point on the plain, they observe that the angle of elevation to the top of the mountain is 29º. From a point 1500 feet closer to the mountain along the plain, they find that the angle of elevation is 34° How high (in feet) is the mountain?

Answer 1

A Soln :- given Let height of mountain is h feet. AB-h feed h feed IN BA 1500 feet 23 34° let CB = x feet K 1500k Now, In A ACB perpendicular f tan 3 4 = AB tano- CB bo pase - 0.6745 h = h=0.67454 In A ADB, tan 29° AB DB AB DetCB h 1500 tu 0.5543 = h 1500 + x 3 h = 0.554 3livo + x) from ea & (ii) we get

0.67 454 0.55431 1500tu) = 831.45 +0.55434 = 0.67450-0.55434 831.45 - 0.1202 H = 831.45 ha 831.45 D. 1202 - 6917. 22 13 feel from ea(i) h = 0.67.454 = 0.6745X 6967.2213 h = 4665.blo feed height of mountain = h = 4665.66 feet Ang soln :- sin (45°) 119904 (2) tre 1 Cos1 450) 1 / 39r+(2) от tanluso) [1 chel 450) = Isart (2) 07 see (45) Isart (2) Cot (450) 1 Ans

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