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8. Solve for currents in the branches for Fig. 34-21. Re: 31 x 125) MN
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Thanks for asking ..In KCL for lon 20 (x+2) + 2x+x-650 zon 6v . -1-4780] Current through 500 = I, = x=(12) = 2.104A) And Current through lon= * 0

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8. Solve for currents in the branches for Fig. 34-21. Re: 31 x 125) MN
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