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Question Help O A survey of 25 randomly selected customers found the ages shown in years)....
13 Question Help o A survey of 25 randomly selected customers found the ages shown (in...
13 Question Help o A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.32 years and the standard deviation is 10.06 years. a) What is the standard error of the mean? b) How would the standard error change if the sample size had been 100 instead of 25? (Assume that the sample standard deviation didn't change.) 36 43 26 28 30 37 39 15 46 41 24 21 47 40 21 37 38...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 33.60 years and the standard deviation is 9.52 years a) Construct a 90% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed that the standard deviation was known to be 10.0 years?...
A survey of 25 randomly selected customers found the ages shown? (in years). The mean is...
A survey of 25 randomly selected customers found the ages shown? (in years). The mean is 33.16 years and the standard deviation is 9.21 years. 47 35 45 21 30 42 49 29 28 35 27 29 45 35 11 34 28 33 44 39 34 25 34 32 18 a) What is the 90% confidence interval for the mean age of all customers assuming that the assumptions and conditions for the confidence interval have been met? b) What is...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.28 years and the standard deviation is 9.35 31 21 44 32 34 11 48 42 23 45 39 35 31 28 29 43 34 37 20 44 33 27 24 a) Construct a 80% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of...
years. A survey of 25 randomly selected customers found the ages shown (in years). The mean...
years. A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.84 years and the standard deviation is 8.84 25 39 43 25 42p a) Construct a 99% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence 23 28 42 45 31 interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.32 yea...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.32 years and the standard deviation is 8.72 25 37 27 32 46 32 17 27 30 36 42 33 30 41 13 27 44 26 35 32 28 30 49 25 44 years a) How many degrees of freedom does the t-statistic have? b) How many degrees of freedom would the t-statistic have if the sample size had been 400? a) The t-statistic...
A survey of 25 randomly selected customers found the ages shown (in years) The mean is...
A survey of 25 randomly selected customers found the ages shown (in years) The mean is 32.68 years and the standard deviation is 9 47 years a) How many degrees of freedom does the t-statistic have? b) How many degrees of freedom would the t-statistic have if the sample size had been 400? 25 25 22 38 420 25 26 37 34 39 46 37 24 13 45 20 42 17 48 34 32 35 39 40 32 a) The...
33 46 48 21 30 32 10 31 20 29 A survey of 25 randomly selected...
33 46 48 21 30 32 10 31 20 29 A survey of 25 randomly selected customers found the ages shown (in years). The mean is 31.76 years and the standard deviation is 10.37 years. a) Construct a 98 % confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence 20 38 40 35 40 interval have been met. 22 37 10 41 26 b) How large is the margin of error?...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.00 years and the standard deviation is 9.99 3 years. a Construct a 99% confidence interval for the mean age of all customers, assuming that the assumptions and conditions or the con interval have been met b) How large is the margin of error? c) How would the confidence interval change i you had assumed that the standard deviation was known to be 10.0...
A store owner surveyed 25 randomly selected customers and found the ages shown (in years). The...
A store owner surveyed 25 randomly selected customers and found the ages shown (in years). The mean is 32.36 and the standard deviation is 11.79. The owner wants to know f the mean age of all customers is 36 years old. Use the given information to complete parts a through . 14 12 18 22 16 42 48 44 28 40 41 3743 44 38 16 20 39 48 31 30 34 21 47 36 a) What is the null...
13 Question Help o A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.32 years and the standard deviation is 10.06 years. a) What is the standard error of the mean? b) How would the standard error change if the sample size had been 100 instead of 25? (Assume that the sample standard deviation didn't change.) 36 43 26 28 30 37 39 15 46 41 24 21 47 40 21 37 38...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 33.60 years and the standard deviation is 9.52 years a) Construct a 90% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed that the standard deviation was known to be 10.0 years?...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.28 years and the standard deviation is 9.35 31 21 44 32 34 11 48 42 23 45 39 35 31 28 29 43 34 37 20 44 33 27 24 a) Construct a 80% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of...
years. A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.84 years and the standard deviation is 8.84 25 39 43 25 42p a) Construct a 99% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence 23 28 42 45 31 interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.32 years and the standard deviation is 8.72 25 37 27 32 46 32 17 27 30 36 42 33 30 41 13 27 44 26 35 32 28 30 49 25 44 years a) How many degrees of freedom does the t-statistic have? b) How many degrees of freedom would the t-statistic have if the sample size had been 400? a) The t-statistic...
A survey of 25 randomly selected customers found the ages shown (in years) The mean is 32.68 years and the standard deviation is 9 47 years a) How many degrees of freedom does the t-statistic have? b) How many degrees of freedom would the t-statistic have if the sample size had been 400? 25 25 22 38 420 25 26 37 34 39 46 37 24 13 45 20 42 17 48 34 32 35 39 40 32 a) The...
33 46 48 21 30 32 10 31 20 29 A survey of 25 randomly selected customers found the ages shown (in years). The mean is 31.76 years and the standard deviation is 10.37 years. a) Construct a 98 % confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence 20 38 40 35 40 interval have been met. 22 37 10 41 26 b) How large is the margin of error?...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.00 years and the standard deviation is 9.99 3 years. a Construct a 99% confidence interval for the mean age of all customers, assuming that the assumptions and conditions or the con interval have been met b) How large is the margin of error? c) How would the confidence interval change i you had assumed that the standard deviation was known to be 10.0...
A store owner surveyed 25 randomly selected customers and found the ages shown (in years). The mean is 32.36 and the standard deviation is 11.79. The owner wants to know f the mean age of all customers is 36 years old. Use the given information to complete parts a through . 14 12 18 22 16 42 48 44 28 40 41 3743 44 38 16 20 39 48 31 30 34 21 47 36 a) What is the null...
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