Question

PROBLEM 4: (30 POINTS) A 1,000 lb. WEIGHT IS HUNG FROM THE END OF A PIPE WHICH IS FASTENED TO A BALL & SOCKET JOINT AT A, AND SUPPORTED BY TWO CABLES CB & BD AS SHOWN. NEGLECTING THE WEIGHT OF THE PIPE, DETERMINE THE FORCES IN BOTH CABLES AND THE SUPPORT REACTION AT A. D Cable 4 60° 1 C. B Cable 1.000 lb 3 А Bar Ball & Socket Joint 6'

Answer 1

Support reaction at A = Axial force = 1250 lb
Tension in BC = 652.4 lb
Tension in BD = 706.3 lb

from given figure, E 4 60 1000 16. * Ropes BC and BD are in horizontal plane * Rod AB is perfectly in a vertical plane. let axial force in rod be f. (compressive) In A ABE, vertical 1000l = 4/5 I f Sin 37" : 3 equilibelum of B, 카 E 6 Resolving f, flo37° 1+ 3 370 B 5 A = 1000 lb 4f 5 fə 1250 lb as с 653 D In ABCD let tension in 6 13 53 4 T₂ T 60 3, BD = Ti с Т. Horizontal equilibrium 0 of B. Resolving T, & Tz Te los do T, 1053 T, Sin 53 = T₂ Singo T, x4- Ta xß3 Tsingo 2 T, Sing3 Ti = T2 x 33 x 3 750 Also T, Cos S3° + T₂ Cabo - 36/ (T3 x 503)x 3 + Text, 750 = Tz 652.4 lb =) Tension in Bc 652.4 lb T, T₂ x 56 706.3 lb - Tension in BD, 706.3 lb 8