speed of lump just before the impact
but =0 initial speed
h = 1.45m
v = sqrt(2 * 10 * 1.45) = 5.4 m/s
change in momentun
where = 5.38m/s
= 0 just after the impact
impulse = 0.35 * 5.38 = 1.87 kg m/s
B
impulse exerted by surface is equal to the impulse on lump = 1.87 kgm/s
so
integration is area under the graph =0.5*5.5*10^(-3)*Fmax = 1.87
Fmax = 680 N
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