Question

FA FB Fc с D E А B Lac LCD LDE LEB Determine the maximum absolute value of the bending moment in this beam. To do this you will probably need to draw a shear and moment diagram to determine where it occurs. The dimensions and forces on the beam are the following: FA = 104 lb, FB = 277 lb, Fc = 104.8 lb, Lac = 14.9 in., LcD = 18.1 in., LDE = 24.6 in., LEB = 10.3 in. The answer should be in lb.in with 1 digit of accuracy.

Answer 1

FA A Leo IDE LES Lac Rc = 244.6eb FREE 211-266 170.6eb 104-5 104 lb Sheen hore Disam 1538-26 Uboin Beading Diego hon 1549.6 db.in 1078-18 lb in given data LA 14.9 in Lip : 18.1 in FA = 104 lb FB 277eb Fc = 104.8 lb LDE 94.6 in LED 10.3 in FA+ FB + Fc - RETRE 14 lb + 27716 + 10t.slb Retre Ret RE 485.5lb

take Moment about a FAX LAC + REX (Lothe) tak bent Flotte B) 104 x 4.9+ RE (18.1 + 54.6) S70X 18.5 + 104.8 ( 18 14 04.64 10.3) RE 2 11.2 b from ean Rc 274.6 lb Shears fore siagram Assumption 11 I! tve shear fore -Vetro Shears for From left side SF at A - Joy eb - 104 eb SF between Alc 170.6 lb SF at a - 104 +374.6 SF between cro 170.6 lb SF ato 170.6 - 277 -106 on eb SF bekweeen DRE -106 qeb 101.8 Sľ cet E -106.4 +211.2 104.8 eb SF beloce E & B 104.8 eb SF at B (from Right side)

Bending remont singsoon 6 saggim Bondry Merre (the 317 ครู 44sc ๆ opast (-ve) from left erde BOTA 0 lb.in Bri of a - 104 X 14.9 - 15496 eboin Bl at o -104 X114.9 +18-) + 294.6 x 18.1 = 1538.26 lb.in Br at o - 104 x (14.9 +18.1 +246) + 274.6(18.1+246) 222 X 24.10 - 1079.18 lbrin (61) at B olbain I from right side) Momont es Marimum absolute value of the Bending 1549.6 ebin