10) A 100-g of ice at -10°C is placed in a lake whose temperature is 25°C....
A 39 g ice cube at -69°C is placed in a lake whose temperature is 65°C. Calculate the change in entropy of the cube-lake system as the ice cube comes to thermal equilibrium with the lake. The specific heat of ice is 2220 J/kg-K. (Hint: Will the ice cube affect the temperature of the lake?) Numbe UnitšT J/k the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work
A 24 g ice cube at -26°C is placed in a lake whose temperature is 26°C. Calculate the change in entropy of the cube-lake system as the ice cube comes to thermal equilibrium with the lake. The specific heat of ice is 2220 J/kg·K. (Hint: Will the ice cube affect the temperature of the lake?)
A 82 g ice cube at -90°C is placed in a lake whose temperature is 63°C. Calculate the change in entropy of the cube-lake system as the ice cube comes to thermal equilibrium with the lake. The specific heat of ice is 2220 J/kg·K. (Hint: Will the ice cube affect the temperature of the lake?)
A 56 g ice cube at -31°C is placed in a lake whose temperature is 83°C. Calculate the change in entropy of the cube-lake system as the ice cube comes to thermal equilibrium with the lake. The specific heat of ice is 2220 J/kg·K. (Hint: Will the ice cube affect the temperature of the lake?)
You have a block of ice at a temperature of -100°C. This block of ice is made from 180g H2O. The block of ice will be heated continually until it becomes super-heated steam at a temperature of 200°C Cice = 2.03 J/g-K ΔHfus=6.01 kJ/mol Cwater = 4.18 J/g-K Csteam = 1.84 J/g-K ΔHvap=40.67 kJ/mol What is the enthalpy change raising the temperature of 180 g of ice at −100 °C to 0°C? What is the enthalpy change upon melting 180...
You Answered Correct Answer Your answer is partially correct. A374 g block of copper whose temperature is 305 K is placed in an insulating box with a 568 g block of lead whose temperatureis 189 K. (a) What is the equilibrium temperature of the two-block system? (b) What is the change in the internal energy of the two- block system between the initial state and the equilibrium state? (c)What is the change in the entropy of the two-block system? The...
An insulated Thermos contains 135 g of water at 86.5 ˚C. You put in a 7.06 g ice cube at 0.00 ˚C to form a system of ice + original water. The specific heat of liquid water is 4190 J/kg•K; and the heat of fusion of water is 333 kJ/kg. What is the net entropy change of the system from then until the system reaches the final (equilibrium) temperature?
An insulated Thermos contains 143 g of water at 82.8 ˚C. You put in a 9.07 g ice cube at 0.00 ˚C to form a system of ice + original water. The specific heat of liquid water is 4190 J/kg•K; and the heat of fusion of water is 333 kJ/kg. What is the net entropy change of the system from then until the system reaches the final (equilibrium) temperature?
An insulated Thermos contains 116 g of water at 89.5 ˚C. You put in a 7.91 g ice cube at 0.00 ˚C to form a system of ice + original water. The specific heat of liquid water is 4190 J/kg•K; and the heat of fusion of water is 333 kJ/kg. What is the net entropy change of the system from then until the system reaches the final (equilibrium) temperature?
Calculate the change in entropy that occurs when 18.02 g of ice at –17.5°C is placed in 90.08 g of water at 100.0°C in a perfectly insulated vessel. Assume that the molar heat capacities for H2O(s) and H2O(l) are 37.5 J K^-1 mol^-1 and 75.3 J K^-1 mol^-1, respectively, and the molar enthalpy of fusion for ice is 6.01 kJ/mol. Change in entropy = ______J/K