Here ,
for the R8 and R10 in series
R11 = 10 + 2 = 12 ohm
for R11 in parallel to R9
R12 = 12 * 6/(12 + 6)
R12 = 4 Ohm
for R12 and R4 in series
R13 = 4 + 8
R13 = 12 Ohm
for R13 and R6 in parallel
R14 = 12 * 8/(12 + 8)
R14 = 4.8 Ohm
for R5 and R14 in series
R15 = 4.8 + 4
R15 = 8.4 Ohm
for R4 and R15 in parallel
R16 = 8.4 * 8/(8.4 + 8)
R16 = 4.1 Ohm
for R3 and R16 in series
R17 = 4 + 4.1 = 8.1 Ohm
for R17 and R2 in parallel
R18 = 8.1 * 8/(8.1 + 8)
R18 = 4.025 Ohm
for R1 and R18 in series
Req = 4.025 + 6
Req = 10.025 Ohm
tge equivalent resistance of the circuit is 10.025 Ohm
2)
current in battery = V/Req
current in battery = 10/10.025
current in battery = 1 A
3)
the current is flowing from the positive terminal of battery
hence it is clockwise
STEP BY STEP SOLUTION PLEASE!! 1. What is the equivalent resistance of the above circuit? 2....
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