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W hat mass of chromium could be deposited by elect
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Answer #1

Cr3+ + 3e = Cr

Charge = current * time

= 10 A * (60*60)s

= 36000 C

No of moles of electron flowed

= 36000 / 96500

= 0.373 moles

As 1 mole of Cr3+ is reduced by 3 moles of electrons, so 0.124 moles of Cr3+ is reduced by 0.373 moles of electrons.

Mass of Cr deposited

= 0.124 * molar mass of Cr

= 0.124 * 52.01 g

= 6.47 g

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