Question

Given the circuit below, compute the effective (rms) value of the voltage in the secondary ( ). Please note that = Veno Numerical values: vy(t) = 240 cos (3770v.i. - 3A rms, R = 5092. Note: The numerical answer is accepted with an error tolerance of +0.3 • Example: If the correct solution is 4.36, any solutions in the range [4.33 - 4.39) is accepted as valid ial posib + Rin Vin(t) Ideal Transformer

Answer 1

Ans)

Given

$v_{in}(t)=240cos(377t)\: \: V\rightarrow phasor(RMS)\rightarrow \vec{V_{in}}=\frac{240}{\sqrt{2}}e^{j0}$

$\vec{V_{in}}=169.71e^{j0}\: \: V$

$\vec{I_{a}}=3\: \: A$

Now by Kirchhoff's voltage law

$\vec{V_{a}}=\vec{V_{in}}-\vec{I_{a}}R=169.71e^{j0}-3*50$

$\vec{V_{a}}=19.706e^{j0}\: \: V$

turns ratio is given as $N_{1}:N_{2}=12:4$

the secondary voltage is gvien as

$\vec{V_{b}}=\vec{V_{a}}*\frac{N_{2}}{N_{1}}=19.706e^{j0}*\frac{4}{12}=6.568e^{j0}\: \: V$

$\vec{V_{b}}=6.568e^{j0}\: \: V$

so answer asked is

$\mathbf{\tilde{V_{b}}=6.568\: \: V}$