0.800 mg = (0.800 / 1000) g
The equation is as follows-
AgNO3 + KCl → AgCl + KNO3
according to the equation:
1mol AgNO3 reacts with 1 mol KCl
Molar mass KCl = Molar mass of Potassium + Molar mass of Chlorine ( K + Cl)
Molar mass KCl = 39.1+35.5 = 74.6g/mol
Which leads us to
(0.800/1000) / 74.6 = 1.072 x 10 -5 mol KCl [ mass divided by molar mass ]
We have 1.072 x 10 -5 mol KCl, therefore you have 1.072 x 10 -5 mol AgNO3 in 25.0ml
Mol AgNO3 in 1000ml = (Number of moles of AgNO3) * 1000/volume of AgNO3
Mol AgNO3 in 1000ml = (1.072 x 10 -5) * 1000/25.0 = 4.288 x 10 -4 mol AgNO3 per litre.
Molarity of AgNO3 solution = 4.288 x 10-4 M
Cheers and Good Luck!!
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