Question

molarity of acid: 0.1435M

volume:25ml

1. Use the molar mass and moles of acetic acid to determine the mass of the acetic acid in the 25.00-ml sample. 2. Calculate the mass/volume percentage (m/v %) by dividing the mass of acetic acid in grams by the volume of the vinegar sample in mL and multiplying by 100. 3. For the reaction of sodium hydroxide solution with a solution of hydrochloric acid: a. Write a balanced molecular equation for the reaction, including phase labels. b. What is the molarity of the hydrochloric acid solution if 14.87 mL of HCl requires 23.76 mL of a 0.675 M sodium hydroxide solution to react with it completely? 4. For the reaction of calcium hydroxide solution with a solution of phosphoric acid: a. Write a balanced molecular equation for the reaction, including phase labels. b. What volume (in mL) of a 0.03455 M calcium hydroxide solution would be needed to completely react with 32.76 mL of a 0.0215 M phosphoric acid solution? Rep your answer with the proper number of significant digits. 5. What is the molarity of a sulfuric acid solution if 23.76 mL of a 0.798 M solution is diluted to a final volume of 250 mL? Report your answer with the proper number of significant digits.

Answer 1

Given concentration = 0.1435M. 0.1435 moles Voliere = 25ml molar mass of acetic acid=60g/ow we know that Molarity = mass - x 1000 molar mass mace Vanmi) number of moles = _ o mass molay mass substitute all the values o. 14 35= mass 60 x 1000 as = mass = ((60) (0.1435) (25)) g 1000 mass of acetic acid = 0.215959 mass of Acetic acid = 0.215 g C Scanned with CamScanner

e mass of Acetic acido. 2159 poluve of Solution - 25 ml i (mv)% = Mass mass - X100 Yo Volume of solution 0:2159 -x 25 mi 100 % .5 0.8666 1: /m) % = 0.86 % CSScanned with CamScanner