If a_(1)=0 and a_(n+1)=2a_(n)-3, find a_(4)
Write out the first five terms of the sequence with, \(\left[\frac{\ln(n)}{n+1}\right]_{n=1}\), determine whether the sequence converges, and if so find its limit. Enter the following information for \(a_{n}=\frac{\ln (n)}{n+1}\). \(a_{1}=\) \(a_{2}=\) \(a_{3}=\) \(a_{4}=\) \(a_{5}=\) \(\lim_{n \rightarrow \infty} \frac{\ln (n)}{n+1}=\) (Enter DNE if limit Does Not Exist.) Does the sequence converge (Enter "yes" or "no").
|(1 point) Let -2 -4 -4 -4 A = -3 -6 -6 -6 Find a spanning set for the null space of A. 1 N(A) span - 0 0 |(1 point) Let -2 -4 -4 -4 A = -3 -6 -6 -6 Find a spanning set for the null space of A. 1 N(A) span - 0 0
2. Given k(2x + 3y) if a_ 0.1.2: у-0, 1. plx,y) - is a joint probability mass function(discrete case). a. What is k? b. Find the momen generating function Mx(t) c. Find the conditional probabilities P(Y X), P(Y 0X 1), P(X 1Y 0 2. Given k(2x + 3y) if a_ 0.1.2: у-0, 1. plx,y) - is a joint probability mass function(discrete case). a. What is k? b. Find the momen generating function Mx(t) c. Find the conditional probabilities P(Y X),...
30 01 1. Let A-0 3 4 0 4 3] (a) Find the eigenvalues and their corresponding eigenspaces for A. (b) Is A diagonalisable? If so, find a diagonalisation for A. (c) Find a formula for A" where n is any positive integer
[1 0 O1[i 2 0 3 6. (4) Let A 3 1 0l0 0 3 1. Without multiplying the matrices, 0 -1 1110 0 0 0 (a) Find the dimension of each of the four fundamental subspaces. b have a solution? (b) For what column vector b (b, b2, ba)' does the system AX (c) Find a basis for N(A) and for N(AT). [1 0 O1[i 2 0 3 6. (4) Let A 3 1 0l0 0 3 1. Without...
Find a. b. c. d. e. f. Find N(A) 1 -3 4 -1 9 A = -2 6 -6 -1 -10 -3 9 -6 -6 -3 mo 3 -94 9 a. 1 -2 6 -3 N(A) = -6 -1 -10 Ob. 10 0 N(A) 3 2 0 3 -5 0 N(A) = 0 0 0 2 O d. 2 ܩ ܘ ܚ N(A) 1 0 0 0 2 e. 2. 3 3 -3 6 9 -9 N(A) = -6 -6...
3 and 4 please 1 0 0 3. Find the inverse of A= 0 4 0 by Gauss-Jordan elimination 2 3 1 and check your answer by multiplication. 3 1 2 4. Find the inverse of 2 6 -4 by the cofactor formula. 3 0
Find f(1), f(2), f(3), f(4) and f(5) if f(n) is defined recursively by f(0)=3 and for n=0, 1, 2, ... f(n + 1) = 3f(n) + 7 f(n + 1) = f(n)^2 - 2f(n) - 2
Find N(A) A= 1 -3 4 - 1 9 -2 6 -6 -1 -10 -39 -6 -6 -3 3 -94 9 0 oa. 1 -2 -3 3 - 3 6 9 N(A) = 4 -6 -1 -6 -1 -10 -6 9 9 0 3 0 N(A) 1 0 2 0 N(A) = 2 1 0 -2 0 d. 3 -10 0 N(A) 2 0 0 N(A) -2 6 -3 4 N(A) = -1 -6 -1 -10 9
Find (A) and n(A) A = 1 - 3 4 -1 9 -2 6 -6 -1 -10 - 39 -6 -6 -3 3 -9 4 9 0