Question

Age\Ed H.S AA B.A. М.А 30-50 88 97 250 120 51-70 85 300 150 250 The contingency table gives the breakdown of a random sample of people by age and highest education achieved. You choose one person at random. Find each of the requested probabilities, to two decimal paces. a. P(the person is aged 30 - 50) b. P(the person's highest education is High School) c. P(person's highest education is high school, given they are aged 30-50) d. P(person is aged 30-50 and their highest education is High School) e. P(person is aged 30-50 or their highest education is High School) Enter your answer as a string of 10 digits. The first two digits represent your answer for part a, the second two digits for part b. etc. So if your answers were 0.34,0.45,0.06,0.67,0.89 you would enter 3445066789. Be sure to round each probability correctly to two decimals or you will get marked wrong. Example: 0.634 rounds to 0.63, but 0.635 rounds to 0.64.

Answer 1

som H.S A. A BA M. A Total __ 30-50 8% 97 250 12.0 555 51-70 85 300 150 250 785 Total 173 397 400 370 1340 a) P (the person is aged 30-50) - 535 0-41 1340 b) pl the person highest education is heigh school 173 7340 = 0.13 c) pl person highest education in high given they 88)1340 School aged 30-50 -0.16 555) 1340 이 Person is aged 30-50 and their highest education high school) 88 0:07 1340 their P ( person is aged 30-50 or highest education is High Schero) 173 1340 + 555 1340 88 7340 = 0.48