65.0 mL sample of a 0.102 M potassium sulfate solution is mixed with 38.5 mL of a 0.122 M lead(II) acetate solution and the following precipitation reaction occurs:
K2SO4(aq)+Pb(C2H3O2)2(aq)→2KC2H3O2(aq)+PbSO4(s)
The solid PbSO4 is collected, dried, and found to have a mass of 0.993 g .
a. Define the theoretical yield
b. Define the percent yield.
65.0 mL sample of a 0.102 M potassium sulfate solution is mixed with 38.5 mL of...
A 55.5 mL sample of a 0.106 M potassium sulfate solution is mixed with 40.0 mL of a 0.106 MM lead(II) acetate solution and the following precipitation reaction occurs: K2SO4(aq)+Pb(C2H3O2)2(aq)→2KC2H3O2(aq)+PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 0.991 g . Part (A) Identify the limiting reactant. 1. PbSO4 2. KC2H3O2 3. Pb(C2H3O2)2 4. K2SO4 Part (B) Determine the theoretical yield. mass of PbSO4 = __________ g Part (C) Determine the percent yield. ____________ %
A 55.0 mL sample of a 0.102 M potassium sulfate solution is mixed with 35.0 mL of a 0.114 M lead (II) acetate solution. The solid lead (II) sulfate is collected, dried, and found to have a mass of 1.01 g. The Balanced Reaction is: Pb(CH3COO2)(aq) + K2SO4 --> PbSO4(S) + 2K (aq) + 2CH3COO- (aq) b.Write the net ionic reaction. c.Which ions are spectators? d.Determine the limiting reagent. e. Determine the theoretical yield. f.Determine the percent yield. g. Determine...
You may want to reference (Page) Section 4.4 while completing this problem. A 61.5 mL sample of a 0.122 M potassium sulfate solution is mixed with 37.0 mL of a 0.122 M lead(II) acetate solution and the following precipitation reaction occurs: K2SO4(aq)+Pb(C2H3O2)2(aq)→2KC2H3O2(aq)+PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 1.00 g . Determine the limiting reactant, the theoretical yield, and the percent yield.
A 77.0-mL sample of a 0.203 M potassium sulfate solution is mixed with 55.0 mL of a 0.226 M lead(II) nitrate solution and this reaction occurs: K2SO4(aq) + Pb(NO3)2 (aq) ⟶ 2 KNO3(aq) + PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 3.71 g. Determine the percent yield. 1 mole PbSO4 = 303.26 g Group of answer choices 98.4% 80.0% 120.% 75.7%
A 77.0-ml sample of a 0.203 M potassium sulfate solution is mixed with 52.0 mL of a 0.214 Mlead(11) nitrate solution and this reaction occurs: K2SO4(aq) + Pb(NO3)2 (aq) 2 KNO3(aq) + PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 2.43 g. Determine the percent yield. 1 mole PbSO4 = 303.26g 80.1% O 120% o 58.9% o 72.0%
A 15.0 mL sample of a 1.60 M potassium sulfate solution is mixed with 14.4 mL of a 0.890 M barium nitrate solution and this precipitation reaction occurs: K2SO4(aq)+Ba(NO3)2(aq)→BaSO4(s)+2KNO3(aq) The solid BaSO4 is collected, dried, and found to have a mass of 2.52 g . Determine the limiting reactant, the theoretical yield, and the percent yield.
A 77.0-ml sample of a 0.203 M potassium sulfate solution is mixed with 55.0 mL of a 0.226 M lead(II) nitrate solution and this reaction occurs: K2SO4(aq) + Pb(NO3)2 (aq) + 2 KNO3(aq) + PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 3.71 g. Determine the percent yield. 1 mole PbSO4 = 303.26 g Hydrazine, N2H4, is a liquid used as a rocket fuel. It reacts with oxygen to yield nitrogen gas and water....
A 20.0 mL sample of a 1.12 M potassium sulfate solution is mixed with 144 mL.of a 0 880 M barium nitrate solution and this precipitation reaction occurs K2SO4(aq)+Ba(NOs)2 (aq) BaSo.(s)+2KNOs (aq) The solid BaSO4 is collected, dried, and found to have a mass of 2 52 g Determine the imiting reactant, the theoretical yield, and the percent yield Part A Determine the limiting reactant Express your answer as a chemical formula. ΑΣφ Request Answer Submit We were unable to...
A 29.3-mL sample of a 1.22 M potassium chloride solution is mixed with 14.5 mL of a 0.860 M lead(II) nitrate solution and this precipitation reaction occurs: 2KCl(aq)+Pb(NO3)2(aq)→PbCl2(s)+2KNO3(aq) The solid PbCl2 is collected, dried, and found to have a mass of 2.46 g. Determine the limiting reactant, the theoretical yield, and the percent yield.
Question 5 5 pts A 77.0-mL sample of a 0.203 M potassium sulfate solution is mixed with 55.0 mL of a 0.226 M lead(II) nitrate solution and this reaction occurs: K2SO4(aq) + Pb(NO3)2 (aq) - 2 KNO3(aq) + PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 2.62 g. Determine the percent yield. 1 mole PbSO4 = 303.26g 91.1% 120% 69.5% 80.1% Question 29 5pi If 1.85 g MgO is combined with enough 1.00 M...