Homework Answers
Sr + 3/2O2 +C(graphite)SrCO3
1 mole of stontium carbonate formation gives = 1.22*103Kj/mole
147.6 gm of SrCO3 formation released = 1.22*103ki/mole
1.95g of SrCO3 formation released = 1.22*103*1.95/147.6 = 16.11KJ/mole
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also last 2 questions.!
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