Question

java

/* Q2 (10 pts): Write a method called method that accepts an integer parameter * * * * and returns a sum of the first n terms of the sequence. * In other words, the method should generate the following sequence: 1 + 1/2 + 1/3 + 1/4 + ... 1/n * For example, method2(2) will return 1.5 since 1+1/2 = 1.5 * method2 (15) will return 3.3182289932289937 * You may assume that the parameter n is nonnegative. */ * * * /* Q3 (10 pts): Write a method called method3 that accepts a string as its arameter * and returns a string (last two letters of the parameter). * For example, method3("abcd") should return "cd" method3("EFG") should return "FG". * * * * If the parameter has less than 2 characters, return "Error"*/

Answer 1

2.

The JAVA program with the implementation of method2 is given below,

import java.util.*;
import java.lang.*;
import java.io.*;

class Ideone{
   // Required method2 to calculate the sequence sum
static double method2(int n)
{
double result = 0;
for (int a = 1; a <= n; a++) {
   double temp= (double)1/a;
result = result + temp;
}
return result;
}
  
//Main function
public static void main(String args[])
{
   Scanner scanner = new Scanner( System.in );
       //Taking input
int n=scanner.nextInt();
       //printing output
System.out.println(method2(n));
}
}

SCREENSHOTS

import java.util.; import java.lang.*: import java.io.*; class Ideone // Required method to calculate the sequence sum static double method2(int n) { double result = @; for (int a = 1; a <= n; a++) double temp= (double)1/a; result = result + temp; return result; //Main function public static void main(String args[]) Scanner scanner = new Scanner(System.in); //Taking input int n=scanner.nextInt(); //printing output System.out.println(method2(n));

stdin stdout 3.3182289932289937