Question

Pruuleei 28 25

I will rate. Can you solve it please. thanks

Answer 1

In an electric field E, the torque applied to a dipole P is given vectorially by the cross-product

P x E
The maximum magnitude of that torque is |P|.|E| (it occurs when P and E are perpendicular):
|P|.|E| = (8.2e(-30) C.m) . (3.58e (+8) N/C ) = 2.9356 e(-21) = 2.93 x 10^(-21) N.m

Note that 1 N/C = 1 V/m. So, the electric field mentioned corresponds to
a 358,000 volts difference over a displacement of 1 mm. Just a thought.

(Here I can’t see the value of E because the question is not clear. So i took as a reference value please replace your value in place of 3.58x10⁸ N/C and do this calculation you will get correct answer. I hope you understand.)