Question

The molecule below cannot form an enamine. Wh Myristicin, one of the spice components in nutmeg Gust in time for pumpkin spice season, of course!), is shown below. How would you synthesize the acetal portion of the molecule? What about the terminal alkene portion of the molecule? Vanillin (again, in time for the season of spiced beverages..) is obtained naturally linked to a simple sugar, as shown below. How might you isolate the vanillin? vanillin

Answer 1

Benzaldehyde lacks an alpha proton, so enolate ion cannot be formed and thus formation of anamine becomes difficult with the first molecule shown (benzaldehyde)

retrosynthesis of Meristicin may give the idea about the introduction of acetal group.

Vanillin_

Vani lin OCH3 00M3 Audie, Hydro ње 내 0Hナ OH