Question

During noon time Bob the construction worker who weighs 80kg stands below the sun 1.989x10^30 kg the distance between Bob and the sun is 1.50x10^11

1. What size is the force that the Sun puts on Bob the construction worker

2. find the accel due to Suns gravity on the suns surface. with the radius of the sun being 7.89x10^8

3. find the suns escape speed

please show equations used and work done thank you.

Answer 1

@ @W Gravitational force (F) = G M, M2 Mi and Me are masses and re es distance between them - C=6.67 x 10-11 t = 6.67 x 10-11 X 1.98941030 x 80 (1.5 X10")? F = 0.472 N DRZ a= GM R is radius of sun - LM is mass of oun a = 6,67x10" X 1.989x1030 05 (7.89 x103)? 1 an aur Ja = 1.327x104 m/s² acelanation due to gravity By energy conservation. GM m = 1 mu? V = 26M V R V 24 6.67 X10-" * 1.989 X 103 7.89 X 108 V- 579,904 km/se V = 5.80 X 105 ms.