ln (K2/K1) = (Ea / R) (1/T1 - 1/T2)
T1 = 250C = 298 K K1 = 3.46 x 10-5 s-1
T2 = 550C = 328 K K2 = 1.5 x 10-3 s-1
ln (1.5 x 10-3 / 3.46 x 10-5) = (Ea / 8.314) (1/298 - 1/328)
3.77 = (Ea / 8.314) (0.00335 - 0.00305)
3.77 = (Ea / 8.314) (0.0003)
Ea / 8.314 = 12566.7
Ea = 104479.5 J/mol
Ea = 104.79 KJ / mol
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