Question

Light in vacuum is incident on the surface of a slab of transparent material. In the vacuum the beam makes an angle of 37.1° with the normal to the surface, while in the slab it makes an angle of 16.2° with the normal. What is the index of refraction of the transparent material?

Answer 1

from snells law of refraction

n1*sini = n2*sinr

n1 = refractive index of vacuum = 1

i = angle of incidence in vacuum = 37.1

n2 = refreactive index of material = ?

r = angle made by the light ray inside the material = 16.2

1*sin37.1 = n2*sin16.2

the index of refraction of the transparent material = 2.162 <<<<==============answer