Question

ament/rako Covalent Activity do locator ansignment take e w Toples References 1 .0 Lt p e 66 and temperature of C. As ideal behavior A 2.70 peo p le foto copy a v The moler mass of the unknown as is mol Rweyttir Grow ogrom

Answer 1

Mass of unknown gas(m) = 2.70 g

Volume(V) = 1.50 L

Pressure(P) = 661 mmHg

1 atm = 760 mmHg

So pressure(P) = (661 mmHg)/(760 mmHg)*1.0 atm = 0.869 atm

Temperature(T) = 41.00C (273+41 = 314K)

Using ideal gas equation

PV = nRT

Where , P = pressure , V= volume , n = number of moles ,

R = gas constant (0.08205 L atm / mol K )

T = temperature

n    =     PV/RT   = (0.869 atm)(1.50 L )/( 0.08205 L atm / mol K )(314 K)

n = 0.0505 mol

we know that , moles = mass/molar mass

molar mass = mass/moles =   2.70 g/0.0505 mol = 53.46 g/mol

so the molar mass of unknown gas is 53.46 g/mol