A solenoid of length L = 10 m carrying a current I = 9 A has a magnetic field of 2 x 10-5 T. Calculate the number of turns.
B=Magnetic field due to solenoid= unI
u=Permeability of space
n=N/L=Number of Turns per unit length
N=Number of turns
L=Length
I=Current flowing
B= uNI/L
2*10-5= 1.256*10-6*N*9/10
N=17.69 turns
A solenoid of length L = 10 m carrying a current I = 9 A has a magnetic field of 2 x 10-5 T
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Magnetic Field inside a Very
Long Solenoid Learning Goal: To apply Ampère's law to find the
magnetic field inside an infinite solenoid. In this problem we will
apply Ampère's law, written ?B? (r? )?dl? =?0Iencl, to calculate
the magnetic field inside a very long solenoid (only a relatively
short segment of the solenoid is shown in the pictures). The
segment of the solenoid shown in (Figure 1) has length L, diameter
D, and n turns per unit length with each...
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