Question

solve in detail please

10-21 The net work output and the thermal efficiency for the Carnot and the simple ideal Rankine cycles with steam as the working fluid are to be calculated and compared. Steam enters the turbine in both cases at 5 MPa as a saturated vapor, and the condenser pressure is 50 kPa. In the Rankine cycle. the condenser exit state is saturated liquid and in the Carnot cycle, the boiler inlet state is saturated liquid. Draw the T-s diagrams for both cycles.

Answer 1

P2=83=5mpa @ Carnot cycle 12= soookpa se '= 154.5 kulla Sy = 2.9207 65196 os P2 = 121= 5000 lepa 1-2-3-4 Rankine Cycle hac hg = 279413 /cs/kg 1-2-3-4-) Carnot cych $- $ = 5.992 k3 ligt since Sy = 5 At Pu= Piano Epa Sy=S2 = 5.97343 st Su= Set dy sfg - 2 5:973=110912+tu (6.5819) - Ky= 0.75 hu= hq tauhay - 340.54+0-75123044) = 2070.9 kJ/kg state 14 . s,'= S₂ = 2.9207 hallgid, Pia sokpa Si= Sft da Seg >> 2.92072 100912 it.sey (69019).- fp= 028 ... h= het hup hey = 340.54 +0.2814 (23047) = 989.082 Kgs Net work Wnet = M2-hy) Cheiah,') {2794.3 =20709)-(1545-989.com 27 Wret = 551.982 15/16 WWWWWWUNS

Mariet Weet = 557.982 =557-982 28.340 Csup ham hal (27942-1154-5) Mcannot = 8:34 = 344.7 Ô Rankine cycle Pieso lepă = hy = 340.54 culla, vs 0.001020 mlly P2 = 5000 kpa wpumpa ricpe-Pa) = 0-001030 ( 5000-50) 1 = 5:0985 kilo : h2=hyt wpump.= 340.54 +5.0985 =3450 638 ley de state? Post spoo Kepa >> h2 = 27942/3/by, S7=569737 bollyk state y su=33 - Puso lepa, At Py = Pi = sokon, Sy= S225-973 killgle. i Sy=fft lysfy . I hya hof toe hoy 295-9737409127 5x16 isola) 1 = 340-34+0.75 (2204,7) » Ly -0.25 : = 2070.9 keglla Wnet = (hz-hy) (hr-hi) = (2799.32207019) - (345-638-340 57) = 718.302 1031 Wuet = 718.302 Kulla Rantive - Whet na 718-362 = 0.293 Qrup Chate) 2194.3-345.638) Mrankine = 0.293= 29:34)