Question

C /8 145 [Ab x o . Sign Roll # Name: Experiment 4 Colorimetric Determination of Section: Date: Report Sheet: (Data must be recorded in pen) Trial Concentration (mol/L) Absorbance 0.16 2.432 2 0.24 3.432 3 0.32 4.322 4 0.40 5.444 5 Unknown number 3.756 Concentration of the unknown mol/L (from graph) 2) dvĄ ...

Answer 1

ma tb. y The equation relating concentration and absorbance is of form. so if we subtract y - intercept from absorbance and dinide dinide by slope, we get the concentration. ↑ qy any Absorbance u conc" (mol/etr) → .. first calculating the slope, we take any two (known) readings Trial # and #2) (say مطمام ... slope A Absorbance A concentration 3. 432 - 2. 432 0.24 - 12.5 0.16 slope

Now, to calculate y intercept, me take take anyone reading Lsay Trial #3) and put it in the @quation . ma tc 4.322 12.5 (032) + C → C = 0.322 Now, the equation becomes y = nalius 12.5 x +0.322 Nous putting of Trial #5

3.756 (12.5)(x) +0.322 O. 27472 0.275 mol/ ltr

Note:

Y axis : absorbance

X axis : concentration