2) A mass of 4 kg is moving at 9 m/s in the +x direction which collides inelastically with a mass (mass 2) of 7 kg. After the collision, the masses are moving at 3 m/s in the +x direction. What is the average force on mass 2 in Newtons if the collision takes 0.1 seconds? If in the negative x direction, include a negative sign.
here,
2)
m1 = 4 kg
m2 = 7 kg
initial velocity of 1 , u1 = 9 m/s
the final velocity , v = 3 m/s
let the initial velocity of 2 be u2
using conservation of momentum
m1 *u1 + m2 * u2 = (m1 + m2) * v
4 * 9 + 7 * u2 = ( 4 + 7) * 3
u2 = - 0.43 m/s
the initial velocity of 2 is - 0.43 m/s in -x direction
t = 0.1 s
the average force on m2 , F2 = m2 * ( v - u) /t
F2 = 7 * (3 - (-0.43)) /0.1 N
F2 = 520.1 N
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