Homework Answers
Specific heat of solution= 4.184 J/g°C.
Mass of solution = 260+2.60 = 262.60 g
dH = -mcdT = -262.6*4.184*(26.4-23)
dH= -3735.64 J
Moles of CaCl2 = mass/molar mass
= 2.6/110.98 = 0.02343 mole
Now dH = -3735.64/0.02343 = -159454.36 J/mol
= -159.45 kJ/mol
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