What would be the effect on the tides if (a) the Moon’s mass were doubled, or (b) the distance between the Earth and the Moon were cut in half? Give quantitative answers.
(a) Higher tides.
Doubling the mass of the moon would double the force exerted on the tide.
(b) Lowers the tides.
Halving the distance would quadruple the force, as gravity is inversely proportional to the square of the distance.
What would be the effect on the tides if (a) the Moon’s mass were doubled, or...
18 If the mass of the moon were doubled, and the distance between the earth and the moon were cut in half, then the force of attraction between the earth and the moon would be: A) The same as the original B) Two times the original Four times the original Dy Eight times the original E) One eighth times the original F) One fourth times the original
6. Given that the distance to the Moon is 384000 km, and taking the Moon’s orbit around Earth to be circular, estimate the speed (in kilometers per second) at which the Moon orbits the Earth. 7. The baseline in Figure 0.19 in the textbook is 100 m and the angle at B is 60 degrees. Using the tangent function, calculate the distance from A to the tree Ch. 1 Discussion Questions 2. The benefit of our current knowledge lets us...
if the mass and the radius of the earth were both doubled, your weight as compared to your present weight, would be?
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3. 1 AU = 149 597 970 700 metres, and the Sun’s mass is 1.98855 x 1030 kg. (a) Calculate the apparent tidal force on the two rocks from question 2 due to the Sun, and (b) use your results from questions 2 and 3 to give a qualitative explanation of the difference between spring tides and neap tides. Note: You will have to be careful about significant figures; take the 1-kg mass as an absolute value. Q2 Results 2....
Suppose that the attraction between the moon and the earth were due to Coulomb forces rather than gravitational force. What would be the magnitude of the charge required if equal but opposite charges resided on both earth and moon? Mass of earth = 5.98×1024 kg; mass of moon = 7.35×1022 kg; earth-moon distance = 3.84×108 m.
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The tidal forces between the Earth and the Moon slowed down the Moon's rotation about its own axis until the rotation period became equal to the Moon's orbital period around the Earth as we observe today. The same effect is also slowing down the Earth's rotation about its own axis and increasing the separation \(D\) between the Moon and the Earth at a rate of \(\Delta D / \Delta t=3.8 \mathrm{~cm}\) per year. In this problem, you can ignore the...
please help! answer is shown below but I need help with the process. so please show all work and I will rate!! 5. Suppose that the attraction between the Moon and the Earth were due to Coulomb forces rather than the gravita- tional force. a) What would be the magnitude of the charge required if equal but opposite charges resided on both the Earth and the Moon, and the electrostatic attraction equalled the gravitational one? b) If the Earth were...