Question

Can someone help me fill out this ICE chart and find the Ksp with the given information?

Calibration Curve:

Slope= 817.96

Intercept= 0

Dissolution Nachon BallO3), Bart 210 3 (64) Ksp = [Ba2+] [103] Absorbance os) at equilibrium 0.565 0.664 6.36x10 4 6.91 x 10-A 8.12 x 107 9.6 1x10* 1.30 x 10 0.786 1.061 Calculations Experiment 26, Solubility Product Constant of Barium iodate Mixture #1 110, Initial Equilibrium continued on next page) Volumes used in preapitating Ballos)2 (mL) 0.0200M BLIN, -OSSOM KIOS H20 5.00mL 1.000L 6.00 mL

Answer 1

And Baat + 3 I03 ² ba (103) Оози 0.055M SmL ImL n = MN moles 10-4 5.5-105 At equilibrium lorex 5.5x10-5-2x x conco of Bo (103), at equilibrium is given Lets take first case when [sa (IO3)₂ ] = 6-36*10-4 noles & Polarity & vol. (er ty = 6.36*10-4 x 19mL 2 x 7.632 x 10-6 moles Ba²+ 10 -4 -2 10-9 - 7.632 x 10-6 moles of Ba 2+ = 9.236 x 10-5 moles - Bozt) - 9236x10 - Slote - 7-696x13 10 = - 5.5x 10 x 5.5x105 - 2 (7.632 x 10-6) 3.9736 % Tos 3.311 x 103 M. (103 ] = Stats

6.36 x 10-4 7. 696 x 10-3 (3.311 x 10-3) 2 = 0.0754 x los = 7.54 x 103 Kimilarly, we can calculate for all the cases,