Given wire lenght L = 1.1 m, cross-sectional area A = 1.1*10^-6 m2, current I = 5.6 A, potential difference V = 2.1 V
we know that from Ohm's law V = IR ==> R = V/I =
2.1/5.6 =0.375 ohms
and resistivity rho = R*A/L = 0.375*1.1*10^-6 /1.1 = 375000 ohm
m
now conductivity sigma = 1/ rho = 1/375000 = 2.67*10^-6 (ohm m )^-1
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