Question

Force 6 x3-2 x, find the work in mks units done by the force for a distance of x A) 576000 J 12. in mks units done by the force for a distance of x-4 tox-6 E) 36001. B) 2000 J C) 1540 J D) 1800 J 13. An Atwood's machine with a friction less pulley has massl- 11 kg and is accelerating up at 2.7 m/s. What is the valos o mass 2? A) 1122 kg B) 89.1 kg C) 33.66 kg D) 29.1 kg E) 19.37 kg 14. An 3000-kg car traveling at 50 m/s takes 8 m to stop under full braking, The same car under similar road conditions, traveling at 100 m/s, takes m to stop under full braking. A) 8 B) 16 32 D)3 E) 16 .9 5. A 150 N sled is pulled up a 2s° slope at a constant speed by a force of 130 N. What is the coefficient of kinetic fric between sled and slope? Astudent weighing 10o N climbs a fight of stairs 3.0m high in4s. Whatower reird to perform this tas A))0.1 Hp B) 40 W C) 2.6 Hp D) 0.126 Hp E) 270 w 1900 N/m and compressed by 0.45 m accelerates a 5 kg mass down a friction spring of spring constant of 1 om a height of 9 m. What is the speed of the mass at the bottom of the inclined plane? 14.994 m/s B) 59.5 m/s C) 107.1 m/s D) 25.66 m/s E) 34.272 m/'s oropes are attached to a 40 kg object. The rope with a 50 N force points along a direction 31 from and the other robe with a 70 N force points along a direction 230°. What is the acceleration of the 13 m/s B) 43.4 m/s C) 10.47 m/s D) 9.43 m/s E) 17.112 m/s 063N or is speeding up at 1.2 m/s' a 1300 kg sled with a rope at an angle of 38. The coefficient of
13?

Answer 1

F = 6x^3 - 2x, x = 4 to x = 6 work = integral F.dx = integral_4^6 (6x^3 - 2x)dx = [6/4 times [x^4]_4^6 - [x^2]_4^6] work = [6/4(6^4 -4^4) - (6^2 - 4^2)] = 6540 j mg - T = ma T - 110 = 11 a mg - 110 = (m + 11) 2.7 10 m - 110 = 2.7 m + 2.7 times 11 7.3 m = 1397 m = 19.13 kg v^2 = v^2 + 2as 0 = 2500 + 2a times 8 a = - 156.25 m/s^2 v^2 = v^2 + 2as 0 = (100)^2 + 2(- 156.25)s s = 32 m