Question

Wages (W) and years of education (X) have the following joint distribution: The fractions in the table are probabilities. That is, each cell is the probability that the row and column outcome happen at the same time. • (4 points) Find the marginal probability distribution for wages W. Hint: W takes on four values, you need to find the probability that it equals each one. • (4 points) Find the marginal probability distribution function for education X. • (5 points) Find the conditional expectation E(W|X = x) for each value of X. It should be a single number for each value of x. • (4 points) Find E(W) from the marginal probability function you found earlier. • (5 points) Now suppose I told you about something called the ”law of iterated expectations”. It means the following is true: E(W) = E(E(W|X)) (1) Verify that this is the case by taking the expectation of the variable you generated in part c and comparing it to your answer from part d.

3. Wages (W) and years of education (X) have the following joint distribution: = 14 = 16 X = 18 ။ | X = 10 / = 12 I = 5 IT =

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Page No. Date Ans Joint Prob dirth Toble IX -16 1x=18 P(x=x) 21/100 11100 31100 29/100 W-51101100 51100 W.10 6100 81100 w 3/Page No. Similarly PCX=121320 L P(x:1) = 20, PCxE16) = 20 = P(x=19) 52 Table Mirginel Bob dist of education of 20 loc 13 ConPage No. Date L E (W/x = 10 ) = 2 w lolxsio (ope) - Gyú) + (1x ) + (15 X 2) +(7044) 3.2.5+3+ +1 = 2.5+ 3 +2.25 + 1 = 8.75 E(hPage No. Date Similarly CD E (Wien)- E w fulxong (w/3) /+42073.) = (5x3d +10xt+fis y = 2 2 + 1 2 + 2 / +3 =0.75 +3.5 +5.25 +3

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