Question

Solve. Round to the nearest tenth. Aladder 8 m long is leaning against a building. How high on the building will the ladder reach when the bottom of the ladder is x = 1 m from the building? Need Help? Read it Watch It Talk to a Tutor

Answer 1

> we will eolve this problem by Pythagorean law. The Pythagorean Law states that, in a right-angled triangle ABC BA (as shown in the figure) with base Ão, height BC and hypotenuse Ãc, the relation (AB)² = (Ac)² + (BC)" holds. > solution: te mot R. The ladder at forms a right-angled triangle A ABC with the wall of the building and the base. (as shown in the figure). Here, BD is the wall and AB is the base It is given that AB = x= 1 m. ama AC = 8 m. since SABC is a right-angled triangle so, by Pythagorean Law, we have (AC)² = (AB) ² + (BC) ? => (CC) = (C) - (B) 8", D E om AC = 8m (BC) = 64-1 = 63 BC = 563 = 7.937... ~ 7.9 (Approximately] BC = 7.9 - 8 - 1

on the ladder is So, the ladder will reach 7.gm building when the bottom of the a=1m from the building so, the answer is 17.9 Im.

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