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(3) Two runners, Aiden and Bailey live in towns 22 miles apart and wish to jog to meet up with each other somewhere in the mi
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(3).

Let Aiden and Bailey meet after x hours.

In x hours, Aiden jogs a distance of 5x miles and Bailey jogs a distance of 7x miles. Therefore 5x+7x = 22 or, 12x = 22 so that x = 22/12 = 11/6.

Thus, it will take 11/6 hours before Aiden and Bailey meet.

Aiden will jog a distance of 5*11/6 = 55/6 miles and Bailey will jog a distance of 7*11/6 = 77/6 miles when they meet.

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