Homework Answers
Mass of sucrose = 45.2 g.
Molar mass of sucrose = 342.3 g/mol
Moles of sucrose = mass / molar mass = 45.2 / 342.3 = 0.132 mol
Weight of solvent = 155 g. = 0.155 kg
Molality = moles of solute / weight of solvent in kg = 0.132 / 0.155 = 0.852 mol/kg
Kb = 0.512 degree C/m
Boiling point of water = 100 degree C
Elevation in boiling point = Kb X m
Tb - T0 = 0.512 X 0.852
Tb - 100 = 0.436
Tb = 0.436 + 100
Tb = 100.436
Tb = Boiling poing of solution = 100.436 degree C
(C) 100.44 degree C
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