. From pH of the following solutions, calculate the concentration (molarity) of [H+] and identify the solution as acidic, basic or neutral/nearly neutral (3 pts).
3.1) pH = 2.6
3.2) pH = 6.87
1)PH = -log [H+]
Given,ph =2.6
[H+] =10-ph
[H+]= 10-2.6
[H+] = 2.51 ×10-3
solution is acidic .Because ph is less than 7 .
2)PH = -log [H+] ,Given ph =6.87
[H+] =10-6.87
[H+]=1.349 ×10-7
Solution is nearly neutral because its ph is approximately near to 7.
Acid solution below 7 ph
Neutral solution 7 ph
Basic solution above 7 ph
Nearly neutral solution near to 7 ph
. From pH of the following solutions, calculate the concentration (molarity) of [H+] and identify the...
Calculate the [H+] in the following solutions, given their pH, and identify the solution as acidic, basic or neutral. pH = 2.5 pH = 11.7 pH = 6.8 pH = 3.31
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