A skier starting from rest coasts down a mountain that makes an angle of 25 degrees...
A skier starting from rest coasts down a mountain that makes an angle of 25 degrees with the horizontal. The coefficient of kinetic friction between her skis and the snow is 0.200. She coasts for a distance of 10.4 m before coming to the edge of a cliff. Without slowing down, she skis off the cliff and lands dwonhill at a point whose vertical distance is 3.50 m below the edge.
How fast is she going before she lands?
Please draw necessary diagrams and show equations when solving. Thank you!
Homework Answers
Using conservation of energy.
Net change in Kinetic energy = Net change in Potential energy + work done by friction.
So 0.5 * m* v^2 = m *g * ( 3.5 + 10.4 * sin 25 ) - 0.2 * m * g* 10.4
So v =sqrt ( 2 * 9.8 * ( 3.5 + 10.4 * sin 25 - 0.2* 10.4 ))
So v = 10.67 m/s
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