Question

dast 1.5 m FA-500 N The cable AB excretes a tension Fas Of SOON (a) Write the vector expression for the tension Fas (60 pts) (b) Determine the scalar projection of Fae along AC (40 pts) Q2. Bonus) What is the Moment about point.A? (10 pts) 4 m m 50 3 kN

Answer 1

Q2(Bonus) solution

A 3 Costi 3 KN (3 Sins) EMA Moment about point A {MA = (3 sin se') (4 m) + (3 cos so) (0.4 m) MA - 9.96 KN.M Ang.

ünit vector for AB QAB (22-NA) C + (4-Ya) +(28-29) ī I CAB) Al*, 4,2) = 10, +,0) C(2,0,4) B (my, z) = (-2, 0,1-5) eine) = 1272+(4124 (0)2 = 6 m 16--21%+ (9-0)2+ (0-1)2 = 4.72 m A LAB) (-2-0) î + (0-4) Ĵ + 11.5-0) û こ 4.72 QAD (-27 - 45 + 1sî) ) PAR (FASI QAB = 56: 1 (-2î - 4ſ +1's f) 4-72 FAB = -212 î 424 Ĵ + 159 Ã part (b) Scalar projectim of FAB along AC = FAB Caso AB and between Al. o is angle use triangle ABC 4.72 m 1100) - 64)2+(0)2+(4-1-5)? i Coso AB²+ Ace – Bc? 2 (AB) (AC) (4-72)+(612-(4-72)2 2(4-72) (6) = 0.43 projection of For along Al = (500) Coso - 500 (0.63) =317-8 N

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