What is the change in length of a 30.0-cm-long column of mercury if its temperature changes from 37.0ºC to 40.0ºC , assuming the mercury is constrained in a tube so that the volume only changes in one dimension? (answer in ×10−6 m
gamma = 181*10^-6
initial volume = V1 = A*L1
final volume = V2 = A*L2
here area A remains same
gamma = dV/(v1*dT)
gamma = A*dL/dT
181*10^-6 = dL/(30*(40-37))
dL = 16290*10^-6 m
What is the change in length of a 30.0-cm-long column of mercury if its temperature changes...
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