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At 305 K, this reaction has a Kc value of 0.0242. Calculate Kp at 305 K....
At 385 K, this reaction has a Kc value of 0.0660 2X(g)2 Y(g) 2Z(g) Calculate Kp at 385 K. Note that the pressure is in units of atmosphere (atm) р Кр
At 315 K, this reaction has a Kc value of 0.0835. X(g) + 3 Y(g) = 2(g) Calculate K, at 315 K. Note that the pressure is in units of atmosphere (atm). Kp =
At 439 K, this reaction has a Kc value of 0.0569. 2X(g)+2Y(g)−⇀↽−Z(g) Calculate KpKp at 439 K. Note that the pressure is in units of atmosphere (atm).
At 435 K, this reaction has a Kc value of 0.0694. X(g) + 3 Y(g) = Z(g) Calculate Ko at 435 K. Note that the pressure is in units of atmosphere (atm). K,
At 417 K, this reaction has a K value of 0.0825. X(g) +3 Y(g) Zg) Calculate Kp at 417 K. Note that the pressure is in units of atmosphere (atm). Kp enms of use consact us help sm inoge Careors Photo Booth ptivacy policy
At 457 K, this reaction has a Ke value of 0.0489. Calculate p at 457 K. Number Note that the pressure is in units of atmosphere (atm) K-
At 323 K, this reaction has a K, value of 0.0873. X(g) + 3 Y(g) = 2(g) Calculate K, at 323 K. Note that the pressure is in units of atmosphere (atm). Kp =
At 447 K, this reaction has a K, value of 0.0193. X(g) + 2Y(g) = 2(g) Calculate Ko at 447 K. Note that the pressure is in units of atmosphere (atm). Kp careerspracy policy terms of use contact us help
1-Consider the following reaction at equilibrium. The Kc value for the reaction at 295 K is 1.20 x 10-4. NH4HS (s) ⇌ NH3 (g) + H2S (g) a. Calculate the Kp value at 295 K. b. Determine the partial pressure of each gas at equilibrium. c. Calculate the Kc value of the following reaction. 3NH3 (g) + 3H2S (g) ⇌ 3NH4HS (s)
DQuestion 1 2 pts Select the statements below that are TRUE. Kc and Kp are the same thing as the k (rate constant) that you learned about before. Kc has units of molarity and Kp has units of pressure D Kp uses the same equation as Kc, but with pressure instead of concentration Kc is equal to Kp when the number of moles of gas (n) doesn't change. Solids and liquid are not included in the Kc and Kp equations...