Question

Given the standard enthalpy changes for the following two reactions: (1) 4C(s) + 5H2(g)-------> C4H10(g)...... ΔH°...

Given the standard enthalpy changes for the following two reactions:

(1) 4C(s) + 5H2(g)-------> C4H10(g)...... ΔH° = -125.6 kJ

(2) C2H2(g) ----> 2C(s) + H2(g)......ΔH° = -226.7 kJ

what is the standard enthalpy change for the reaction:

(3) 2C2H2(g) + 3H2(g)--------->C4H10(g)......ΔH° = ? kj

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Answer #1

2 * (2)
2 C2H2 (g) ---------> 4C (s) + 2H2 (g) ; ΔH° = -453.4 kJ
Add equation (1) to the above equation then you will obtain equation (3) i.e)
2 C2H2 (g) + 3 H2 (g) ---------> C4H10 (g) ......... ΔH° = -125.6kJ + (-453.4)kJ
ΔH° = -579 kJ ------ [ for (3) ]

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