A 10.0 N melon is accelerated uniformly from rest at a rate of 2.50 m/s2. What is the kinetic energy of this object after it has accelerated at a distance of 15.0 m?
As you know weight of the melon
W=mg =10
m=10/g =10/9.8 =1.02 kg
Using equation of the motion
V^2=u^2+2aS
Here u=0, a=2.5m/s^2 , S=15 m
V^2=0+2×2.5×15
V=
m/s
Kinetic energy K=mV^2/2
K=1.02×75/2
K=38.25 J. Answer
A 10.0 N melon is accelerated uniformly from rest at a rate of 2.50 m/s2. What...
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