Question

Calculate the values ​​of U1, U3, U4, U5, I1, I2, I3, I4, RT and IT in the circuit below.

Ry=32 Iz? Rz=682 U=6V 1=? Uz=? Rs=? 1=? Ry=622 V=? Ri=352 HE U=? U= 24 V

Answer 1

By using ohm's law and node voltage method, we can find the above given terms.

0 7 Given circuit is, R₂ = 32 I R3=662 U2=60 'Iz Uz = ? Rag = 7 U4=? R4=652 NI; = ? U5 = ? YI4=? Ri=32 + U,=? U-24 V we can modified above above circuit as below, There, Ra, R1 and Rs resistors are an series and R and are in parallel R4 R2 = 32 U2 = 60 YIz YIL Ք, ՀՅ U,=? R3=600 Ry=652 Uz = ? + U4 c? U=24v IA Rs =702 Us=? So , + By using Node - Voltage method, find a V-24 V 3+3+7 vi [is +5 +6] - O she + 6 bo 24 13 T y (0.41025] = 1.84615 T u - 1.84615 0.41025 4.50

2 I, = I4 ; because they 24-4.5 3+3+1 = 1.5A 13 13 "I4 =15A 7 Iz 24.5 = 6 and - = 4.5 R4 6 ,مملح * UI * U4 Ry 1 R34=302 Series from ciecuit, are in series. So, I = 24-vi 19.500 R3 = 0.75 A Iz V = 0.75 we have to determine , U3, Uy, UG, Ry and It' using Ohm's law = I, *RI les *3 = 4,50 Uz = Iz *R 0.75*6 = 45V Iz = 0.75*6 = 4,5V and Ug = P4 * Rs = 1.5*7 = 105 u To find Rp i voltage source will be shorted. So, R₂ = 30 R4=62 => R2,R, and Rs are en series- R25 = R1 + R₂ + Rg=3+3+7=132 and R₂ con & Ry are an paralle), → = R311 Rg =6116 6+ 16 = 3 1 2 = 30 Now, circuit will, 7 Here, Rizs and By are in Res=32 So, Rj 513+3=1612 find Rtor Ry=32 Rz=62 Rs = 72 R34²

(3 a. Ry=162 To find If Jy ó- T Now, replacing Rt with all resistors now the given circuit will + Ry = 162 U=24v IT 24 - :. It = 1.5A = Rj 16