Question

QUESTION 5 light of frequency 1.5 x1014 Hz in air is incident at an angle of 31 degrees on a liquid with a refractive index 2.4. What is the wavelength of the light in the liquid, in units of nm? QUESTION 6 Which type of electromagnetic radiation lies betweon infra red and ultraviolet in the electromagnetic spectrum? O visible light ○Xrays O radio microwaves

Answer 1

We have the equation T_n = T_0/n T_n = wave length of light in 2^nd medium T_0 = wave length of light in 1^st medium n = refractive index of 2^nd medium \r\n given frequency of light is 1^st medium, = f = 1.5 times 10614 therefore wavelength in 1^st medium = T_0 = c/f T_0 = c/f c = velocity of light in air = 3 times 1068 m/s f = frequency rightdoublearrow T_0 = 3 times 10^8/1.5 times 10^14 = 197238.6 m \r\n wavelength in 2^nd medium T_n = T-0/n rightdoublearrow T_n = 197238.6/2.9 T_n = 82182.75 m T_n = 82182.75 times 10^9 nm 1 m = 10^9 nm \r\n or if in question, frequency is 1.5 times 10^14 Hz instead of 1.5 times 10^19 then T_n = T_0/n n = 2.4 T_0 = ? T_0 = c/f = 3 times 10^8 m/s/1.5 times 10^14 Hz T_0 = 2 times 10^-6 m