Solution:- If we consider the ionization of water then it gives H+ and OH- and the concentrations are equal.
Given pH is 8.571
So, [H+] = 10-8.571 = 2.685 x 10-9 M
Since, [H+] = [OH-]
So, [OH-] = 2.685 x 10-9 M
pOH = - log 2.685 x 10-9
pOH = 8.571
For water,
pKw = pH + pOH
pKw = 8.517 + 8.517
pKw = 17.03
We know that, Kw = 10-pKw
Kw = 10-17.03
Kw = 9.33 x 10-18
This calculated value is almost equal to the given value of Kw so This one is True.
Kw value increases as the temperature is increased and so the percent ionization also increases.
Pure water has equal concentrations of H+ and OH- that makes it neutral. So, the false statement is, " pure water is basic at 60 degree C."
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