A uniform slender bar of mass M = 3.2 kg and length L = 1.78 m...

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A uniform slender bar of mass M = 3.2 kg and length L = 1.78 m is translating on the smooth horizontal x-y plane with a veloc

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L=1:78m m = 0.36 kg Vm z 5.52 m/s S Given That M = 3.2 kg VM = 1: = 1.80 m Steb I Calculation of centre of of system mars 니다 Stebol Angular Momentum Conservation about C! NU mvXG 1 M12+M 2 au 12 + mf = xa)?+ m (XC) 0:36x5524024 = (13:24 [1:23242:21(2

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A uniform slender bar of mass M = 3.2 kg and length L = 1.78 m...

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A uniform slender bar of mass M = 3.2 kg and length L = 1.78 m...

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