P0 = $1000
r = 0.08
e=2.72 (rounded to nearest 2 decimals places)
For ease of calculation, let us break down the formula
t (in years) | P ($) |
---|---|
1 | 1083.28 |
2 | 1173.32 |
3 | 1270.94 |
4 | 1376.68 |
5 | 1491.22 |
6 | 1615.29 |
7 | 1749.68 |
8 | 1895.26 |
9 | 2052.94 |
10 | 2223.75 |
11 | 2408.76 |
12 | 2609.17 |
13 | 2826.26 |
14 | 3061.40 |
15 | 3316.11 |
16 | 3592.01 |
17 | 3890.87 |
18 | 4214.59 |
19 | 4565.24 |
20 | 4945.07 |
21 | 5356.50 |
22 | 5802.16 |
23 | 6284.90 |
24 | 6807.81 |
25 | 7374.22 |
26 | 7987.75 |
27 | 8652.34 |
28 | 9372.21 |
29 | 10151.98 |
30 | 10996.62 |
Ofcourse, the more decimal places you consider for the value of e, more accurate results you would get.
The graphs
a)
b)
c)
d)
Question 3 When interest is compounded continuously, the following equation repre- sents the growth of your...