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Question 3 When interest is compounded continuously, the following equation repre- sents the growth of your savings: P Poe I
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Answer #1

P0 = $1000

r = 0.08

e=2.72 (rounded to nearest 2 decimals places)

For ease of calculation, let us break down the formula

0.08t P PePo(e)1000 x (e0u1000 x 1.0832

t (in years) P ($)
1 1083.28
2 1173.32
3 1270.94
4 1376.68
5 1491.22
6 1615.29
7 1749.68
8 1895.26
9 2052.94
10 2223.75
11 2408.76
12 2609.17
13 2826.26
14 3061.40
15 3316.11
16 3592.01
17 3890.87
18 4214.59
19 4565.24
20 4945.07
21 5356.50
22 5802.16
23 6284.90
24 6807.81
25 7374.22
26 7987.75
27 8652.34
28 9372.21
29 10151.98
30 10996.62

Ofcourse, the more decimal places you consider for the value of e, more accurate results you would get.

The graphs

a)

2 14 Ti 8 6 4 5050505050505050505050505 CICI ㅣ 1 0 0 9 9 8 8 7 7 6 6 5 5 4 4 3 3 1 CI-- ($) umouryb)Current Balance 12500 12000 11500 11000 10500 10000 9500 9000 8500 8000 7500 7000 6500 6000 5500 5000 4500 4000 3500 3000 250c)o Current Balance 4.6 4.4 4.2 3.8 3.6 3.4 3.2 6 2.8 2.6 2.4 1.4 0.8 0.6 0.4 0.2 4 6 8 10 12 14 16 18 20 24 26 28 30 Time (yead)o Current Balance 4.6 4.3 ii 않 3.4 3.3 26 24 1.8 16 1.4 ()않 0.6 0.4 0.2 0 0 1 02 04 0.5 09 Time log base 10) 1.1 1.4 1.5

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