SS zds, s 0:3 evaluate the surface integral where is the cone z = V x²...

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Answer 1

Answer #1

OC O 3 If zds z = between xyplane Jazyl where is Sis the cone and z=2 Il zds Ble Of(x, y, z(x,y)) Si + (83j2 1683) da f(x, y,

Answer 2

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