Question

(a) Explain the difference between the enthalpy of formation of liquid and gaseous water,-286 and - 242 kJ/mol, respectively, at 298 K. b) Explain why the enthalpy of vaporization of water at 100 oC (40.7 kJ/mol) is lower than at 25 oC (44 kJ/mol)

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Answer #1

1.Reaction of gaseous H2 and O2 to yield one mole of liquid water releases 286 kJ of heat. If the H2O is formed in the gaseous state, the energy release will be smaller (around 242 kJ).

During change of phase of water some heat is required and this is noting both latent heat of vaporization for formation of 2 moles of water= (286-242)/2=44Kj/mol

2.It is lowers since this is essentially the ratio between P-T , the lower T, we need energy to evaporate + to heat , wheras at high T, we only need to evaporate.

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